Solve 115/3-(593/352*35/3)

$$\frac { 115 } { 3 } - ( \frac { 593 } { 352 } \times \frac { 35 } { 3 } )$$

Evaluate

$$\frac{6575}{352}\approx 18.678977273$$

Solution Steps

Multiply \frac{593}{352} times \frac{35}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{115}{3}-\frac{593\times 35}{352\times 3}$$

Do the multiplications in the fraction \frac{593\times 35}{352\times 3}.

$$\frac{115}{3}-\frac{20755}{1056}$$

Least common multiple of 3 and 1056 is 1056. Convert \frac{115}{3} and \frac{20755}{1056} to fractions with denominator 1056.

$$\frac{40480}{1056}-\frac{20755}{1056}$$

Since \frac{40480}{1056} and \frac{20755}{1056} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40480-20755}{1056}$$

Subtract 20755 from 40480 to get 19725.

$$\frac{19725}{1056}$$

Reduce the fraction \frac{19725}{1056} to lowest terms by extracting and canceling out 3.

$$\frac{6575}{352}$$

Factor

$$\frac{5 ^ {2} \cdot 263}{2 ^ {5} \cdot 11} = 18\frac{239}{352} = 18.678977272727273$$