Solve for k
k = \frac{48}{19} = 2\frac{10}{19} \approx 2.526315789
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33=-3\left(2\times 2+1\right)+\left(3\times 6+1\right)k
Multiply both sides of the equation by 6, the least common multiple of 2,6.
33=-3\left(4+1\right)+\left(3\times 6+1\right)k
Multiply 2 and 2 to get 4.
33=-3\times 5+\left(3\times 6+1\right)k
Add 4 and 1 to get 5.
33=-15+\left(3\times 6+1\right)k
Multiply -3 and 5 to get -15.
33=-15+\left(18+1\right)k
Multiply 3 and 6 to get 18.
33=-15+19k
Add 18 and 1 to get 19.
-15+19k=33
Swap sides so that all variable terms are on the left hand side.
19k=33+15
Add 15 to both sides.
19k=48
Add 33 and 15 to get 48.
k=\frac{48}{19}
Divide both sides by 19.
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