Solve 11/15-3/20+7/45=

$$\frac { 11 } { 15 } - \frac { 3 } { 20 } + \frac { 7 } { 45 } =$$

Evaluate

$$\frac{133}{180}\approx 0.738888889$$

Solution Steps

Least common multiple of 15 and 20 is 60. Convert \frac{11}{15} and \frac{3}{20} to fractions with denominator 60.

$$\frac{44}{60}-\frac{9}{60}+\frac{7}{45}$$

Since \frac{44}{60} and \frac{9}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{44-9}{60}+\frac{7}{45}$$

Subtract 9 from 44 to get 35.

$$\frac{35}{60}+\frac{7}{45}$$

Reduce the fraction \frac{35}{60} to lowest terms by extracting and canceling out 5.

$$\frac{7}{12}+\frac{7}{45}$$

Least common multiple of 12 and 45 is 180. Convert \frac{7}{12} and \frac{7}{45} to fractions with denominator 180.

$$\frac{105}{180}+\frac{28}{180}$$

Since \frac{105}{180} and \frac{28}{180} have the same denominator, add them by adding their numerators.

$$\frac{105+28}{180}$$

Add 105 and 28 to get 133.

$$\frac{133}{180}$$

Factor

$$\frac{7 \cdot 19}{2 ^ {2} \cdot 3 ^ {2} \cdot 5} = 0.7388888888888889$$