Solve 11/12-7/12=(4/12)*2/6

$$\frac { 11 } { 12 } - \frac { 7 } { 12 } = ( \frac { 4 } { 12 } ) \cdot \frac { 2 } { 6 }$$

Verify

Solution Steps

Since \frac{11}{12} and \frac{7}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-7}{12}=\frac{4}{12}\times \frac{2}{6}$$

Subtract 7 from 11 to get 4.

$$\frac{4}{12}=\frac{4}{12}\times \frac{2}{6}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}=\frac{4}{12}\times \frac{2}{6}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}=\frac{1}{3}\times \frac{2}{6}$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{1}{3}=\frac{1}{3}\times \frac{1}{3}$$

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{3}=\frac{1\times 1}{3\times 3}$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$\frac{1}{3}=\frac{1}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{1}{3} and \frac{1}{9} to fractions with denominator 9.

$$\frac{3}{9}=\frac{1}{9}$$

Compare \frac{3}{9} and \frac{1}{9}.

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