Solve 11/10+frac{sqrt{121}}{100}-14/20

$$\frac { 11 } { 10 } + \frac { \sqrt { 121 } } { 100 } - \frac { 14 } { 20 }$$

Evaluate

$$\frac{51}{100}=0.51$$

Solution Steps

Calculate the square root of 121 and get 11.

$$\frac{11}{10}+\frac{11}{100}-\frac{14}{20}$$

Least common multiple of 10 and 100 is 100. Convert \frac{11}{10} and \frac{11}{100} to fractions with denominator 100.

$$\frac{110}{100}+\frac{11}{100}-\frac{14}{20}$$

Since \frac{110}{100} and \frac{11}{100} have the same denominator, add them by adding their numerators.

$$\frac{110+11}{100}-\frac{14}{20}$$

Add 110 and 11 to get 121.

$$\frac{121}{100}-\frac{14}{20}$$

Reduce the fraction \frac{14}{20} to lowest terms by extracting and canceling out 2.

$$\frac{121}{100}-\frac{7}{10}$$

Least common multiple of 100 and 10 is 100. Convert \frac{121}{100} and \frac{7}{10} to fractions with denominator 100.

$$\frac{121}{100}-\frac{70}{100}$$

Since \frac{121}{100} and \frac{70}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{121-70}{100}$$

Subtract 70 from 121 to get 51.

$$\frac{51}{100}$$

Factor

$$\frac{3 \cdot 17}{2 ^ {2} \cdot 5 ^ {2}} = 0.51$$