Solve 109-11b/18>0

$$\frac { 109 - 11 b } { 18 } > 0$$

Solve for b

$$b<\frac{109}{11}$$

Solution Steps

Multiply both sides by 18. Since 18 is positive, the inequality direction remains the same. Anything times zero gives zero.

$$109-11b>0$$

Subtract 109 from both sides. Anything subtracted from zero gives its negation.

$$-11b>-109$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$b<\frac{-109}{-11}$$

Fraction \frac{-109}{-11} can be simplified to \frac{109}{11} by removing the negative sign from both the numerator and the denominator.

$$b<\frac{109}{11}$$