Solve 100-3[-1+(2-6)^2]/|20-25|

$$\frac { 100 - 3 [ - 1 + ( 2 - 6 ) ^ { 2 } ] } { | 20 - 25 | }$$

Evaluate

$$11$$

Solution Steps

Subtract 6 from 2 to get -4.

$$\frac{100-3\left(-1+\left(-4\right)^{2}\right)}{|20-25|}$$

Calculate -4 to the power of 2 and get 16.

$$\frac{100-3\left(-1+16\right)}{|20-25|}$$

Add -1 and 16 to get 15.

$$\frac{100-3\times 15}{|20-25|}$$

Multiply 3 and 15 to get 45.

$$\frac{100-45}{|20-25|}$$

Subtract 45 from 100 to get 55.

$$\frac{55}{|20-25|}$$

Subtract 25 from 20 to get -5.

$$\frac{55}{|-5|}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.

$$\frac{55}{5}$$

Divide 55 by 5 to get 11.

$$11$$

Factor

$$11$$