Solve 10x/x+3-1

$$\frac { 10 x } { x + 3 } - 1$$

Evaluate

$$\frac{3\left(3x-1\right)}{x+3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+3}{x+3}.

$$\frac{10x}{x+3}-\frac{x+3}{x+3}$$

Since \frac{10x}{x+3} and \frac{x+3}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10x-\left(x+3\right)}{x+3}$$

Do the multiplications in 10x-\left(x+3\right).

$$\frac{10x-x-3}{x+3}$$

Combine like terms in 10x-x-3.

$$\frac{9x-3}{x+3}$$

Differentiate w.r.t. x

$$\frac{30}{\left(x+3\right)^{2}}$$

Steps Using Derivative Rule for Quotient

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+3}{x+3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10x}{x+3}-\frac{x+3}{x+3})$$

Since \frac{10x}{x+3} and \frac{x+3}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10x-\left(x+3\right)}{x+3})$$

Do the multiplications in 10x-\left(x+3\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10x-x-3}{x+3})$$

Combine like terms in 10x-x-3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{9x-3}{x+3})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(x^{1}+3\right)\frac{\mathrm{d}}{\mathrm{d}x}(9x^{1}-3)-\left(9x^{1}-3\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+3)}{\left(x^{1}+3\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(x^{1}+3\right)\times 9x^{1-1}-\left(9x^{1}-3\right)x^{1-1}}{\left(x^{1}+3\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(x^{1}+3\right)\times 9x^{0}-\left(9x^{1}-3\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Expand using distributive property.

$$\frac{x^{1}\times 9x^{0}+3\times 9x^{0}-\left(9x^{1}x^{0}-3x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{9x^{1}+3\times 9x^{0}-\left(9x^{1}-3x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Do the arithmetic.

$$\frac{9x^{1}+27x^{0}-\left(9x^{1}-3x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Remove unnecessary parentheses.

$$\frac{9x^{1}+27x^{0}-9x^{1}-\left(-3x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Combine like terms.

$$\frac{\left(9-9\right)x^{1}+\left(27-\left(-3\right)\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Subtract 9 from 9 and -3 from 27.

$$\frac{30x^{0}}{\left(x^{1}+3\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{30x^{0}}{\left(x+3\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{30\times 1}{\left(x+3\right)^{2}}$$

For any term t, t\times 1=t and 1t=t.

$$\frac{30}{\left(x+3\right)^{2}}$$