Evaluate
\frac{2x+3}{5\left(x+7\right)}
Expand
\frac{2x+3}{5\left(x+7\right)}
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\frac{\left(10x^{2}+17x+3\right)\left(x+2\right)}{\left(5x+10\right)\left(5x^{2}+36x+7\right)}
Divide \frac{10x^{2}+17x+3}{5x+10} by \frac{5x^{2}+36x+7}{x+2} by multiplying \frac{10x^{2}+17x+3}{5x+10} by the reciprocal of \frac{5x^{2}+36x+7}{x+2}.
\frac{\left(x+2\right)\left(2x+3\right)\left(5x+1\right)}{5\left(x+2\right)\left(x+7\right)\left(5x+1\right)}
Factor the expressions that are not already factored.
\frac{2x+3}{5\left(x+7\right)}
Cancel out \left(x+2\right)\left(5x+1\right) in both numerator and denominator.
\frac{2x+3}{5x+35}
Expand the expression.
\frac{\left(10x^{2}+17x+3\right)\left(x+2\right)}{\left(5x+10\right)\left(5x^{2}+36x+7\right)}
Divide \frac{10x^{2}+17x+3}{5x+10} by \frac{5x^{2}+36x+7}{x+2} by multiplying \frac{10x^{2}+17x+3}{5x+10} by the reciprocal of \frac{5x^{2}+36x+7}{x+2}.
\frac{\left(x+2\right)\left(2x+3\right)\left(5x+1\right)}{5\left(x+2\right)\left(x+7\right)\left(5x+1\right)}
Factor the expressions that are not already factored.
\frac{2x+3}{5\left(x+7\right)}
Cancel out \left(x+2\right)\left(5x+1\right) in both numerator and denominator.
\frac{2x+3}{5x+35}
Expand the expression.
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Limits
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