Solve 10a-20/a^2*3a^2/5*1/a^2-4a+4

$$\frac { 10 a - 20 } { a ^ { 2 } } \cdot \frac { 3 a ^ { 2 } } { 5 } \cdot \frac { 1 } { a ^ { 2 } - 4 a + 4 }$$

Evaluate

$$\frac{6}{a-2}$$

Short Solution Steps

Multiply \frac{10a-20}{a^{2}} times \frac{3a^{2}}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(10a-20\right)\times 3a^{2}}{a^{2}\times 5}\times \frac{1}{a^{2}-4a+4}$$

Cancel out a^{2} in both numerator and denominator.

$$\frac{3\left(10a-20\right)}{5}\times \frac{1}{a^{2}-4a+4}$$

Multiply \frac{3\left(10a-20\right)}{5} times \frac{1}{a^{2}-4a+4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(10a-20\right)}{5\left(a^{2}-4a+4\right)}$$

Factor the expressions that are not already factored.

$$\frac{3\times 10\left(a-2\right)}{5\left(a-2\right)^{2}}$$

Cancel out 5\left(a-2\right) in both numerator and denominator.

$$\frac{2\times 3}{a-2}$$

Expand the expression.

$$\frac{6}{a-2}$$

Expand

$$\frac{6}{a-2}$$

Short Solution Steps

Multiply \frac{10a-20}{a^{2}} times \frac{3a^{2}}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(10a-20\right)\times 3a^{2}}{a^{2}\times 5}\times \frac{1}{a^{2}-4a+4}$$

Cancel out a^{2} in both numerator and denominator.

$$\frac{3\left(10a-20\right)}{5}\times \frac{1}{a^{2}-4a+4}$$

Multiply \frac{3\left(10a-20\right)}{5} times \frac{1}{a^{2}-4a+4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(10a-20\right)}{5\left(a^{2}-4a+4\right)}$$

Factor the expressions that are not already factored.

$$\frac{3\times 10\left(a-2\right)}{5\left(a-2\right)^{2}}$$

Cancel out 5\left(a-2\right) in both numerator and denominator.

$$\frac{2\times 3}{a-2}$$

Expand the expression.

$$\frac{6}{a-2}$$