Solve 10-(3*2^2/(1+10^2)-2^2

$$\frac { 10 - ( 3 \times 2 ^ { 2 } } { ( 1 + 10 ^ { 2 } ) - 2 ^ { 2 } }$$

Evaluate

$$\frac{958}{97}\approx 9.87628866$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$10-\frac{3\times 4}{1+10^{2}-2^{2}}$$

Multiply 3 and 4 to get 12.

$$10-\frac{12}{1+10^{2}-2^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$10-\frac{12}{1+100-2^{2}}$$

Add 1 and 100 to get 101.

$$10-\frac{12}{101-2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$10-\frac{12}{101-4}$$

Subtract 4 from 101 to get 97.

$$10-\frac{12}{97}$$

Convert 10 to fraction \frac{970}{97}.

$$\frac{970}{97}-\frac{12}{97}$$

Since \frac{970}{97} and \frac{12}{97} have the same denominator, subtract them by subtracting their numerators.

$$\frac{970-12}{97}$$

Subtract 12 from 970 to get 958.

$$\frac{958}{97}$$

Factor

$$\frac{2 \cdot 479}{97} = 9\frac{85}{97} = 9.876288659793815$$