Solve 10/9b^2-d/54b

$$\frac { 10 } { 9 b ^ { 2 } } - \frac { d } { 54 b }$$

Evaluate

$$\frac{60-bd}{54b^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 9b^{2} and 54b is 54b^{2}. Multiply \frac{10}{9b^{2}} times \frac{6}{6}. Multiply \frac{d}{54b} times \frac{b}{b}.

$$\frac{10\times 6}{54b^{2}}-\frac{db}{54b^{2}}$$

Since \frac{10\times 6}{54b^{2}} and \frac{db}{54b^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10\times 6-db}{54b^{2}}$$

Do the multiplications in 10\times 6-db.

$$\frac{60-db}{54b^{2}}$$

Factor

$$\frac{60-bd}{54b^{2}}$$