Solve 10/3-5/3(-4)+7/2+7/8(-4)=(4)-1

$$\frac { 10 } { 3 } - \frac { 5 } { 3 } ( - 4 ) + \frac { 7 } { 2 } + \frac { 7 } { 8 } ( - 4 ) = ( 4 ) - 1$$

Verify

Solution Steps

Express \frac{5}{3}\left(-4\right) as a single fraction.

$$\frac{10}{3}-\frac{5\left(-4\right)}{3}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Multiply 5 and -4 to get -20.

$$\frac{10}{3}-\frac{-20}{3}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Fraction \frac{-20}{3} can be rewritten as -\frac{20}{3} by extracting the negative sign.

$$\frac{10}{3}-\left(-\frac{20}{3}\right)+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

The opposite of -\frac{20}{3} is \frac{20}{3}.

$$\frac{10}{3}+\frac{20}{3}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Since \frac{10}{3} and \frac{20}{3} have the same denominator, add them by adding their numerators.

$$\frac{10+20}{3}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Add 10 and 20 to get 30.

$$\frac{30}{3}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Divide 30 by 3 to get 10.

$$10+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Convert 10 to fraction \frac{20}{2}.

$$\frac{20}{2}+\frac{7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Since \frac{20}{2} and \frac{7}{2} have the same denominator, add them by adding their numerators.

$$\frac{20+7}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Add 20 and 7 to get 27.

$$\frac{27}{2}+\frac{7}{8}\left(-4\right)=4-1$$

Express \frac{7}{8}\left(-4\right) as a single fraction.

$$\frac{27}{2}+\frac{7\left(-4\right)}{8}=4-1$$

Multiply 7 and -4 to get -28.

$$\frac{27}{2}+\frac{-28}{8}=4-1$$

Reduce the fraction \frac{-28}{8} to lowest terms by extracting and canceling out 4.

$$\frac{27}{2}-\frac{7}{2}=4-1$$

Since \frac{27}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{27-7}{2}=4-1$$

Subtract 7 from 27 to get 20.

$$\frac{20}{2}=4-1$$

Divide 20 by 2 to get 10.

$$10=4-1$$

Subtract 1 from 4 to get 3.

$$10=3$$

Compare 10 and 3.

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