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10+\sqrt{-6}-2x=2\sqrt{-6}
Multiply both sides of the equation by 2.
10+\sqrt{6}i-2x=2\sqrt{-6}
Factor -6=6\left(-1\right). Rewrite the square root of the product \sqrt{6\left(-1\right)} as the product of square roots \sqrt{6}\sqrt{-1}. By definition, the square root of -1 is i.
10+\sqrt{6}i-2x=2\sqrt{6}i
Factor -6=6\left(-1\right). Rewrite the square root of the product \sqrt{6\left(-1\right)} as the product of square roots \sqrt{6}\sqrt{-1}. By definition, the square root of -1 is i.
10+\sqrt{6}i-2x=2i\sqrt{6}
Multiply 2 and i to get 2i.
\sqrt{6}i-2x=2i\sqrt{6}-10
Subtract 10 from both sides.
-2x=2i\sqrt{6}-10-\sqrt{6}i
Subtract \sqrt{6}i from both sides.
-2x=i\sqrt{6}-10
Combine 2i\sqrt{6} and -\sqrt{6}i to get i\sqrt{6}.
-2x=-10+\sqrt{6}i
The equation is in standard form.
\frac{-2x}{-2}=\frac{-10+\sqrt{6}i}{-2}
Divide both sides by -2.
x=\frac{-10+\sqrt{6}i}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{\sqrt{6}i}{2}+5
Divide i\sqrt{6}-10 by -2.