Solve 1.42-0.35/0.5=5+x/2.86

$$\frac { 1.42 - 0.35 } { 0.5 } = \frac { 5 + x } { 2.86 }$$

Solve for x

$$x=1.1204$$

Steps for Solving Linear Equation

Subtract 0.35 from 1.42 to get 1.07.

$$\frac{1.07}{0.5}=\frac{5+x}{2.86}$$

Expand \frac{1.07}{0.5} by multiplying both numerator and the denominator by 100.

$$\frac{107}{50}=\frac{5+x}{2.86}$$

Divide each term of 5+x by 2.86 to get \frac{5}{2.86}+\frac{x}{2.86}.

$$\frac{107}{50}=\frac{5}{2.86}+\frac{x}{2.86}$$

Expand \frac{5}{2.86} by multiplying both numerator and the denominator by 100.

$$\frac{107}{50}=\frac{500}{286}+\frac{x}{2.86}$$

Reduce the fraction \frac{500}{286} to lowest terms by extracting and canceling out 2.

$$\frac{107}{50}=\frac{250}{143}+\frac{x}{2.86}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{250}{143}+\frac{x}{2.86}=\frac{107}{50}$$

Subtract \frac{250}{143} from both sides.

$$\frac{x}{2.86}=\frac{107}{50}-\frac{250}{143}$$

Least common multiple of 50 and 143 is 7150. Convert \frac{107}{50} and \frac{250}{143} to fractions with denominator 7150.

$$\frac{x}{2.86}=\frac{15301}{7150}-\frac{12500}{7150}$$

Since \frac{15301}{7150} and \frac{12500}{7150} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x}{2.86}=\frac{15301-12500}{7150}$$

Subtract 12500 from 15301 to get 2801.

$$\frac{x}{2.86}=\frac{2801}{7150}$$

Multiply both sides by 2.86.

$$x=\frac{2801}{7150}\times 2.86$$

Convert decimal number 2.86 to fraction \frac{286}{100}. Reduce the fraction \frac{286}{100} to lowest terms by extracting and canceling out 2.

$$x=\frac{2801}{7150}\times \frac{143}{50}$$

Multiply \frac{2801}{7150} times \frac{143}{50} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{2801\times 143}{7150\times 50}$$

Do the multiplications in the fraction \frac{2801\times 143}{7150\times 50}.

$$x=\frac{400543}{357500}$$

Reduce the fraction \frac{400543}{357500} to lowest terms by extracting and canceling out 143.

$$x=\frac{2801}{2500}$$