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1-x<0 x+2<0
For the quotient to be positive, 1-x and x+2 have to be both negative or both positive. Consider the case when 1-x and x+2 are both negative.
x\in \emptyset
This is false for any x.
x+2>0 1-x>0
Consider the case when 1-x and x+2 are both positive.
x\in \left(-2,1\right)
The solution satisfying both inequalities is x\in \left(-2,1\right).
x\in \left(-2,1\right)
The final solution is the union of the obtained solutions.