Solve 1-4ac/4a=8

$$\frac { 1 - 4 a c } { 4 a } = 8$$

Solve for a

$$a=\frac{1}{4\left(c+8\right)}$$

$$c\neq -8$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4a.

$$1-4ac=32a$$

Subtract 32a from both sides.

$$1-4ac-32a=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-4ac-32a=-1$$

Combine all terms containing a.

$$\left(-4c-32\right)a=-1$$

Divide both sides by -4c-32.

$$\frac{\left(-4c-32\right)a}{-4c-32}=-\frac{1}{-4c-32}$$

Dividing by -4c-32 undoes the multiplication by -4c-32.

$$a=-\frac{1}{-4c-32}$$

Divide -1 by -4c-32.

$$a=\frac{1}{4\left(c+8\right)}$$

Variable a cannot be equal to 0.

$$a=\frac{1}{4\left(c+8\right)}\text{, }a\neq 0$$

Solve for c

$$c=-8+\frac{1}{4a}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4a.

$$1-4ac=32a$$

Subtract 1 from both sides.

$$-4ac=32a-1$$

The equation is in standard form.

$$\left(-4a\right)c=32a-1$$

Divide both sides by -4a.

$$\frac{\left(-4a\right)c}{-4a}=\frac{32a-1}{-4a}$$

Dividing by -4a undoes the multiplication by -4a.

$$c=\frac{32a-1}{-4a}$$

Divide 32a-1 by -4a.

$$c=-8+\frac{1}{4a}$$