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\frac{-3}{\sqrt{3}+\sqrt{5}}
Subtract 4 from 1 to get -3.
\frac{-3\left(\sqrt{3}-\sqrt{5}\right)}{\left(\sqrt{3}+\sqrt{5}\right)\left(\sqrt{3}-\sqrt{5}\right)}
Rationalize the denominator of \frac{-3}{\sqrt{3}+\sqrt{5}} by multiplying numerator and denominator by \sqrt{3}-\sqrt{5}.
\frac{-3\left(\sqrt{3}-\sqrt{5}\right)}{\left(\sqrt{3}\right)^{2}-\left(\sqrt{5}\right)^{2}}
Consider \left(\sqrt{3}+\sqrt{5}\right)\left(\sqrt{3}-\sqrt{5}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{-3\left(\sqrt{3}-\sqrt{5}\right)}{3-5}
Square \sqrt{3}. Square \sqrt{5}.
\frac{-3\left(\sqrt{3}-\sqrt{5}\right)}{-2}
Subtract 5 from 3 to get -2.
\frac{-3\sqrt{3}+3\sqrt{5}}{-2}
Use the distributive property to multiply -3 by \sqrt{3}-\sqrt{5}.