Solve 1-05/1-90frac{1{5}}=1+05/1-frac{1{2}}

$$\frac { 1 - 05 } { 1 - 90 \frac { 1 } { 5 } } = \frac { 1 + 05 } { 1 - \frac { 1 } { 2 } }$$

Verify

Solution Steps

Multiply 0 and 5 to get 0.

$$\frac{1-0}{1-\frac{90\times 5+1}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Subtract 0 from 1 to get 1.

$$\frac{1}{1-\frac{90\times 5+1}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Multiply 90 and 5 to get 450.

$$\frac{1}{1-\frac{450+1}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Add 450 and 1 to get 451.

$$\frac{1}{1-\frac{451}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{1}{\frac{5}{5}-\frac{451}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Since \frac{5}{5} and \frac{451}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{\frac{5-451}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Subtract 451 from 5 to get -446.

$$\frac{1}{-\frac{446}{5}}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Divide 1 by -\frac{446}{5} by multiplying 1 by the reciprocal of -\frac{446}{5}.

$$1\left(-\frac{5}{446}\right)=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Multiply 1 and -\frac{5}{446} to get -\frac{5}{446}.

$$-\frac{5}{446}=\frac{1+0\times 5}{1-\frac{1}{2}}$$

Multiply 0 and 5 to get 0.

$$-\frac{5}{446}=\frac{1+0}{1-\frac{1}{2}}$$

Add 1 and 0 to get 1.

$$-\frac{5}{446}=\frac{1}{1-\frac{1}{2}}$$

Convert 1 to fraction \frac{2}{2}.

$$-\frac{5}{446}=\frac{1}{\frac{2}{2}-\frac{1}{2}}$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{5}{446}=\frac{1}{\frac{2-1}{2}}$$

Subtract 1 from 2 to get 1.

$$-\frac{5}{446}=\frac{1}{\frac{1}{2}}$$

Divide 1 by \frac{1}{2} by multiplying 1 by the reciprocal of \frac{1}{2}.

$$-\frac{5}{446}=1\times 2$$

Multiply 1 and 2 to get 2.

$$-\frac{5}{446}=2$$

Convert 2 to fraction \frac{892}{446}.

$$-\frac{5}{446}=\frac{892}{446}$$

Compare -\frac{5}{446} and \frac{892}{446}.

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