Solve 1-4/3/2-frac{8{3}}

$$\frac { 1 - \frac { 4 } { 3 } } { 2 - \frac { 8 } { 3 } }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{3}{3}-\frac{4}{3}}{2-\frac{8}{3}}$$

Since \frac{3}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3-4}{3}}{2-\frac{8}{3}}$$

Subtract 4 from 3 to get -1.

$$\frac{-\frac{1}{3}}{2-\frac{8}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{-\frac{1}{3}}{\frac{6}{3}-\frac{8}{3}}$$

Since \frac{6}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-\frac{1}{3}}{\frac{6-8}{3}}$$

Subtract 8 from 6 to get -2.

$$\frac{-\frac{1}{3}}{-\frac{2}{3}}$$

Divide -\frac{1}{3} by -\frac{2}{3} by multiplying -\frac{1}{3} by the reciprocal of -\frac{2}{3}.

$$-\frac{1}{3}\left(-\frac{3}{2}\right)$$

Multiply -\frac{1}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(-3\right)}{3\times 2}$$

Do the multiplications in the fraction \frac{-\left(-3\right)}{3\times 2}.

$$\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$