Solve 1-1/x^2/x^2+frac{1{x^2}}

$$\frac { 1 - \frac { 1 } { x ^ { 2 } } } { x ^ { 2 } + \frac { 1 } { x ^ { 2 } } }$$

Evaluate

$$\frac{x^{2}-1}{x^{4}+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x^{2}}{x^{2}}.

$$\frac{\frac{x^{2}}{x^{2}}-\frac{1}{x^{2}}}{x^{2}+\frac{1}{x^{2}}}$$

Since \frac{x^{2}}{x^{2}} and \frac{1}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{x^{2}-1}{x^{2}}}{x^{2}+\frac{1}{x^{2}}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{2} times \frac{x^{2}}{x^{2}}.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{2}x^{2}}{x^{2}}+\frac{1}{x^{2}}}$$

Since \frac{x^{2}x^{2}}{x^{2}} and \frac{1}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{2}x^{2}+1}{x^{2}}}$$

Do the multiplications in x^{2}x^{2}+1.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{4}+1}{x^{2}}}$$

Divide \frac{x^{2}-1}{x^{2}} by \frac{x^{4}+1}{x^{2}} by multiplying \frac{x^{2}-1}{x^{2}} by the reciprocal of \frac{x^{4}+1}{x^{2}}.

$$\frac{\left(x^{2}-1\right)x^{2}}{x^{2}\left(x^{4}+1\right)}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{x^{2}-1}{x^{4}+1}$$

Expand

$$\frac{x^{2}-1}{x^{4}+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x^{2}}{x^{2}}.

$$\frac{\frac{x^{2}}{x^{2}}-\frac{1}{x^{2}}}{x^{2}+\frac{1}{x^{2}}}$$

Since \frac{x^{2}}{x^{2}} and \frac{1}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{x^{2}-1}{x^{2}}}{x^{2}+\frac{1}{x^{2}}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{2} times \frac{x^{2}}{x^{2}}.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{2}x^{2}}{x^{2}}+\frac{1}{x^{2}}}$$

Since \frac{x^{2}x^{2}}{x^{2}} and \frac{1}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{2}x^{2}+1}{x^{2}}}$$

Do the multiplications in x^{2}x^{2}+1.

$$\frac{\frac{x^{2}-1}{x^{2}}}{\frac{x^{4}+1}{x^{2}}}$$

Divide \frac{x^{2}-1}{x^{2}} by \frac{x^{4}+1}{x^{2}} by multiplying \frac{x^{2}-1}{x^{2}} by the reciprocal of \frac{x^{4}+1}{x^{2}}.

$$\frac{\left(x^{2}-1\right)x^{2}}{x^{2}\left(x^{4}+1\right)}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{x^{2}-1}{x^{4}+1}$$