Solve 1(2div8)+4*5/frac{1{4}(6-1)}

$$\frac { 1 ( 2 \div 8 ) + 4 \cdot 5 } { \frac { 1 } { 4 } ( 6 - 1 ) }$$

Evaluate

$$\frac{81}{5}=16.2$$

Solution Steps

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{1\times \frac{1}{4}+4\times 5}{\frac{1}{4}\left(6-1\right)}$$

Multiply 1 and \frac{1}{4} to get \frac{1}{4}.

$$\frac{\frac{1}{4}+4\times 5}{\frac{1}{4}\left(6-1\right)}$$

Multiply 4 and 5 to get 20.

$$\frac{\frac{1}{4}+20}{\frac{1}{4}\left(6-1\right)}$$

Convert 20 to fraction \frac{80}{4}.

$$\frac{\frac{1}{4}+\frac{80}{4}}{\frac{1}{4}\left(6-1\right)}$$

Since \frac{1}{4} and \frac{80}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1+80}{4}}{\frac{1}{4}\left(6-1\right)}$$

Add 1 and 80 to get 81.

$$\frac{\frac{81}{4}}{\frac{1}{4}\left(6-1\right)}$$

Subtract 1 from 6 to get 5.

$$\frac{\frac{81}{4}}{\frac{1}{4}\times 5}$$

Multiply \frac{1}{4} and 5 to get \frac{5}{4}.

$$\frac{\frac{81}{4}}{\frac{5}{4}}$$

Divide \frac{81}{4} by \frac{5}{4} by multiplying \frac{81}{4} by the reciprocal of \frac{5}{4}.

$$\frac{81}{4}\times \frac{4}{5}$$

Multiply \frac{81}{4} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{81\times 4}{4\times 5}$$

Cancel out 4 in both numerator and denominator.

$$\frac{81}{5}$$

Factor

$$\frac{3 ^ {4}}{5} = 16\frac{1}{5} = 16.2$$