Solve 1(-2)+3(2)/1+3,1(3)+3(35)/1+3

$$\frac { 1 ( - 2 ) + 3 ( 2 ) } { 1 + 3 } , \frac { 1 ( 3 ) + 3 ( 35 ) } { 1 + 3 }$$

Sort

$$1,27$$

Solution Steps

Multiply 1 and -2 to get -2. Multiply 3 and 2 to get 6.

$$sort(\frac{-2+6}{1+3},\frac{1\times 3+3\times 35}{1+3})$$

Add -2 and 6 to get 4.

$$sort(\frac{4}{1+3},\frac{1\times 3+3\times 35}{1+3})$$

Add 1 and 3 to get 4.

$$sort(\frac{4}{4},\frac{1\times 3+3\times 35}{1+3})$$

Divide 4 by 4 to get 1.

$$sort(1,\frac{1\times 3+3\times 35}{1+3})$$

Multiply 1 and 3 to get 3. Multiply 3 and 35 to get 105.

$$sort(1,\frac{3+105}{1+3})$$

Add 3 and 105 to get 108.

$$sort(1,\frac{108}{1+3})$$

Add 1 and 3 to get 4.

$$sort(1,\frac{108}{4})$$

Divide 108 by 4 to get 27.

$$sort(1,27)$$

The list values are already in order.

$$1,27$$

Evaluate

$$1,27$$