Solve 1(-2)+3(2)/1+31(3)+3(35)/1+3

$$\frac { 1 ( - 2 ) + 3 ( 2 ) } { 1 + 3 } \frac { 1 ( 3 ) + 3 ( 35 ) } { 1 + 3 }$$

Evaluate

$$27$$

Solution Steps

Multiply 1 and -2 to get -2. Multiply 3 and 2 to get 6.

$$\frac{-2+6}{1+3}\times \frac{1\times 3+3\times 35}{1+3}$$

Add -2 and 6 to get 4.

$$\frac{4}{1+3}\times \frac{1\times 3+3\times 35}{1+3}$$

Add 1 and 3 to get 4.

$$\frac{4}{4}\times \frac{1\times 3+3\times 35}{1+3}$$

Divide 4 by 4 to get 1.

$$1\times \frac{1\times 3+3\times 35}{1+3}$$

Multiply 1 and 3 to get 3. Multiply 3 and 35 to get 105.

$$1\times \frac{3+105}{1+3}$$

Add 3 and 105 to get 108.

$$1\times \frac{108}{1+3}$$

Add 1 and 3 to get 4.

$$1\times \frac{108}{4}$$

Divide 108 by 4 to get 27.

$$1\times 27$$

Multiply 1 and 27 to get 27.

$$27$$

Factor

$$3^{3}$$