Solve 1/x-3+3x/x-3+-10/x-3=

$$\frac { 1 } { x - 3 } + \frac { 3 x } { x - 3 } + \frac { - 10 } { x - 3 } =$$

Evaluate

$$3$$

Short Solution Steps

Since \frac{1}{x-3} and \frac{3x}{x-3} have the same denominator, add them by adding their numerators.

$$\frac{1+3x}{x-3}+\frac{-10}{x-3}$$

Since \frac{1+3x}{x-3} and \frac{-10}{x-3} have the same denominator, add them by adding their numerators.

$$\frac{1+3x-10}{x-3}$$

Combine like terms in 1+3x-10.

$$\frac{-9+3x}{x-3}$$

Factor the expressions that are not already factored in \frac{-9+3x}{x-3}.

$$\frac{3\left(x-3\right)}{x-3}$$

Cancel out x-3 in both numerator and denominator.

$$3$$

Factor

$$3$$