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\frac{1}{x-1}-\frac{\left(x-3\right)\left(x^{2}+2x+1\right)}{\left(x^{2}-1\right)\left(x^{2}-6x+9\right)}
Multiply \frac{x-3}{x^{2}-1} times \frac{x^{2}+2x+1}{x^{2}-6x+9} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{x-1}-\frac{\left(x-3\right)\left(x+1\right)^{2}}{\left(x-1\right)\left(x+1\right)\left(x-3\right)^{2}}
Factor the expressions that are not already factored in \frac{\left(x-3\right)\left(x^{2}+2x+1\right)}{\left(x^{2}-1\right)\left(x^{2}-6x+9\right)}.
\frac{1}{x-1}-\frac{x+1}{\left(x-3\right)\left(x-1\right)}
Cancel out \left(x-3\right)\left(x+1\right) in both numerator and denominator.
\frac{x-3}{\left(x-3\right)\left(x-1\right)}-\frac{x+1}{\left(x-3\right)\left(x-1\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x-1 and \left(x-3\right)\left(x-1\right) is \left(x-3\right)\left(x-1\right). Multiply \frac{1}{x-1} times \frac{x-3}{x-3}.
\frac{x-3-\left(x+1\right)}{\left(x-3\right)\left(x-1\right)}
Since \frac{x-3}{\left(x-3\right)\left(x-1\right)} and \frac{x+1}{\left(x-3\right)\left(x-1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{x-3-x-1}{\left(x-3\right)\left(x-1\right)}
Do the multiplications in x-3-\left(x+1\right).
\frac{-4}{\left(x-3\right)\left(x-1\right)}
Combine like terms in x-3-x-1.
\frac{-4}{x^{2}-4x+3}
Expand \left(x-3\right)\left(x-1\right).
\frac{1}{x-1}-\frac{\left(x-3\right)\left(x^{2}+2x+1\right)}{\left(x^{2}-1\right)\left(x^{2}-6x+9\right)}
Multiply \frac{x-3}{x^{2}-1} times \frac{x^{2}+2x+1}{x^{2}-6x+9} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{x-1}-\frac{\left(x-3\right)\left(x+1\right)^{2}}{\left(x-1\right)\left(x+1\right)\left(x-3\right)^{2}}
Factor the expressions that are not already factored in \frac{\left(x-3\right)\left(x^{2}+2x+1\right)}{\left(x^{2}-1\right)\left(x^{2}-6x+9\right)}.
\frac{1}{x-1}-\frac{x+1}{\left(x-3\right)\left(x-1\right)}
Cancel out \left(x-3\right)\left(x+1\right) in both numerator and denominator.
\frac{x-3}{\left(x-3\right)\left(x-1\right)}-\frac{x+1}{\left(x-3\right)\left(x-1\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x-1 and \left(x-3\right)\left(x-1\right) is \left(x-3\right)\left(x-1\right). Multiply \frac{1}{x-1} times \frac{x-3}{x-3}.
\frac{x-3-\left(x+1\right)}{\left(x-3\right)\left(x-1\right)}
Since \frac{x-3}{\left(x-3\right)\left(x-1\right)} and \frac{x+1}{\left(x-3\right)\left(x-1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{x-3-x-1}{\left(x-3\right)\left(x-1\right)}
Do the multiplications in x-3-\left(x+1\right).
\frac{-4}{\left(x-3\right)\left(x-1\right)}
Combine like terms in x-3-x-1.
\frac{-4}{x^{2}-4x+3}
Expand \left(x-3\right)\left(x-1\right).