Solve 1/x=1/32+1/50

$$\frac { 1 } { x } = \frac { 1 } { 32 } + \frac { 1 } { 50 }$$

Solve for x

$$x = \frac{800}{41} = 19\frac{21}{41} \approx 19.512195122$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 800x, the least common multiple of x,32,50.

$$800=800x\times \frac{1}{32}+800x\times \frac{1}{50}$$

Multiply 800 and \frac{1}{32} to get \frac{800}{32}.

$$800=\frac{800}{32}x+800x\times \frac{1}{50}$$

Divide 800 by 32 to get 25.

$$800=25x+800x\times \frac{1}{50}$$

Multiply 800 and \frac{1}{50} to get \frac{800}{50}.

$$800=25x+\frac{800}{50}x$$

Divide 800 by 50 to get 16.

$$800=25x+16x$$

Combine 25x and 16x to get 41x.

$$800=41x$$

Swap sides so that all variable terms are on the left hand side.

$$41x=800$$

Divide both sides by 41.

$$x=\frac{800}{41}$$