Solve 1/t-4/(t+1)^2= | Microsoft Math Solver

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\frac{\left(t+1\right)^{2}}{t\left(t+1\right)^{2}}-\frac{4t}{t\left(t+1\right)^{2}}

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of t and \left(t+1\right)^{2} is t\left(t+1\right)^{2}. Multiply \frac{1}{t} times \frac{\left(t+1\right)^{2}}{\left(t+1\right)^{2}}. Multiply \frac{4}{\left(t+1\right)^{2}} times \frac{t}{t}.

\frac{\left(t+1\right)^{2}-4t}{t\left(t+1\right)^{2}}

Since \frac{\left(t+1\right)^{2}}{t\left(t+1\right)^{2}} and \frac{4t}{t\left(t+1\right)^{2}} have the same denominator, subtract them by subtracting their numerators.

\frac{t^{2}+2t+1-4t}{t\left(t+1\right)^{2}}

Do the multiplications in \left(t+1\right)^{2}-4t.

\frac{t^{2}-2t+1}{t\left(t+1\right)^{2}}

Combine like terms in t^{2}+2t+1-4t.

\frac{t^{2}-2t+1}{t^{3}+2t^{2}+t}

Expand t\left(t+1\right)^{2}.