Solve for n
n=-\frac{2y}{y-2}
y\neq 0\text{ and }y\neq 2
Solve for y
y=\frac{2n}{n+2}
n\neq 0\text{ and }n\neq -2
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2y=2n+2ny\left(-\frac{1}{2}\right)
Variable n cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2ny, the least common multiple of n,y,2.
2y=2n-ny
Multiply 2 and -\frac{1}{2} to get -1.
2n-ny=2y
Swap sides so that all variable terms are on the left hand side.
\left(2-y\right)n=2y
Combine all terms containing n.
\frac{\left(2-y\right)n}{2-y}=\frac{2y}{2-y}
Divide both sides by 2-y.
n=\frac{2y}{2-y}
Dividing by 2-y undoes the multiplication by 2-y.
n=\frac{2y}{2-y}\text{, }n\neq 0
Variable n cannot be equal to 0.
2y=2n+2ny\left(-\frac{1}{2}\right)
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2ny, the least common multiple of n,y,2.
2y=2n-ny
Multiply 2 and -\frac{1}{2} to get -1.
2y+ny=2n
Add ny to both sides.
\left(2+n\right)y=2n
Combine all terms containing y.
\left(n+2\right)y=2n
The equation is in standard form.
\frac{\left(n+2\right)y}{n+2}=\frac{2n}{n+2}
Divide both sides by 2+n.
y=\frac{2n}{n+2}
Dividing by 2+n undoes the multiplication by 2+n.
y=\frac{2n}{n+2}\text{, }y\neq 0
Variable y cannot be equal to 0.
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