Solve for a
a=-\frac{bx}{x-b}
b\neq 0\text{ and }x\neq 0\text{ and }x\neq b
Solve for b
b=-\frac{ax}{x-a}
x\neq 0\text{ and }a\neq 0\text{ and }a\neq x
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bx=ab-ax
Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by abx, the least common multiple of a,x,b.
ab-ax=bx
Swap sides so that all variable terms are on the left hand side.
-ax+ab=bx
Reorder the terms.
\left(-x+b\right)a=bx
Combine all terms containing a.
\left(b-x\right)a=bx
The equation is in standard form.
\frac{\left(b-x\right)a}{b-x}=\frac{bx}{b-x}
Divide both sides by b-x.
a=\frac{bx}{b-x}
Dividing by b-x undoes the multiplication by b-x.
a=\frac{bx}{b-x}\text{, }a\neq 0
Variable a cannot be equal to 0.
bx=ab-ax
Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by abx, the least common multiple of a,x,b.
bx-ab=-ax
Subtract ab from both sides.
\left(x-a\right)b=-ax
Combine all terms containing b.
\frac{\left(x-a\right)b}{x-a}=-\frac{ax}{x-a}
Divide both sides by x-a.
b=-\frac{ax}{x-a}
Dividing by x-a undoes the multiplication by x-a.
b=-\frac{ax}{x-a}\text{, }b\neq 0
Variable b cannot be equal to 0.
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