Solve 1/99*9/9-3/5*4/49

$$\frac { 1 } { 99 } \times \frac { 9 } { 9 } - \frac { 3 } { 5 } \times \frac { 4 } { 49 }$$

Evaluate

$$-\frac{943}{24255}\approx -0.038878582$$

Solution Steps

Divide 9 by 9 to get 1.

$$\frac{1}{99}\times 1-\frac{3}{5}\times \frac{4}{49}$$

Multiply \frac{1}{99} and 1 to get \frac{1}{99}.

$$\frac{1}{99}-\frac{3}{5}\times \frac{4}{49}$$

Multiply \frac{3}{5} times \frac{4}{49} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{99}-\frac{3\times 4}{5\times 49}$$

Do the multiplications in the fraction \frac{3\times 4}{5\times 49}.

$$\frac{1}{99}-\frac{12}{245}$$

Least common multiple of 99 and 245 is 24255. Convert \frac{1}{99} and \frac{12}{245} to fractions with denominator 24255.

$$\frac{245}{24255}-\frac{1188}{24255}$$

Since \frac{245}{24255} and \frac{1188}{24255} have the same denominator, subtract them by subtracting their numerators.

$$\frac{245-1188}{24255}$$

Subtract 1188 from 245 to get -943.

$$-\frac{943}{24255}$$

Factor

$$-\frac{943}{24255} = -0.038878581735724595$$