Solve 1/9x+6=1/3

$$\frac { 1 } { 9 } x + 6 = \frac { 1 } { 3 }$$

Solve for x

$$x=-51$$

Steps for Solving Linear Equation

Subtract 6 from both sides.

$$\frac{1}{9}x=\frac{1}{3}-6$$

Convert 6 to fraction \frac{18}{3}.

$$\frac{1}{9}x=\frac{1}{3}-\frac{18}{3}$$

Since \frac{1}{3} and \frac{18}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{9}x=\frac{1-18}{3}$$

Subtract 18 from 1 to get -17.

$$\frac{1}{9}x=-\frac{17}{3}$$

Multiply both sides by 9, the reciprocal of \frac{1}{9}.

$$x=-\frac{17}{3}\times 9$$

Express -\frac{17}{3}\times 9 as a single fraction.

$$x=\frac{-17\times 9}{3}$$

Multiply -17 and 9 to get -153.

$$x=\frac{-153}{3}$$

Divide -153 by 3 to get -51.

$$x=-51$$