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\frac{16u^{2}-81b^{2}}{144}
Factor out \frac{1}{144}.
\left(4u-9b\right)\left(4u+9b\right)
Consider 16u^{2}-81b^{2}. Rewrite 16u^{2}-81b^{2} as \left(4u\right)^{2}-\left(9b\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\frac{\left(4u-9b\right)\left(4u+9b\right)}{144}
Rewrite the complete factored expression.