Solve 1/9-2/3+13/18-7/6=

$$\frac { 1 } { 9 } - \frac { 2 } { 3 } + \frac { 13 } { 18 } - \frac { 7 } { 6 } =$$

Evaluate

$$-1$$

Solution Steps

Least common multiple of 9 and 3 is 9. Convert \frac{1}{9} and \frac{2}{3} to fractions with denominator 9.

$$\frac{1}{9}-\frac{6}{9}+\frac{13}{18}-\frac{7}{6}$$

Since \frac{1}{9} and \frac{6}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-6}{9}+\frac{13}{18}-\frac{7}{6}$$

Subtract 6 from 1 to get -5.

$$-\frac{5}{9}+\frac{13}{18}-\frac{7}{6}$$

Least common multiple of 9 and 18 is 18. Convert -\frac{5}{9} and \frac{13}{18} to fractions with denominator 18.

$$-\frac{10}{18}+\frac{13}{18}-\frac{7}{6}$$

Since -\frac{10}{18} and \frac{13}{18} have the same denominator, add them by adding their numerators.

$$\frac{-10+13}{18}-\frac{7}{6}$$

Add -10 and 13 to get 3.

$$\frac{3}{18}-\frac{7}{6}$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$\frac{1}{6}-\frac{7}{6}$$

Since \frac{1}{6} and \frac{7}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-7}{6}$$

Subtract 7 from 1 to get -6.

$$\frac{-6}{6}$$

Divide -6 by 6 to get -1.

$$-1$$

Factor

$$-1$$