Solve 1/9-[-3(-8/6)+16]

$$\frac { 1 } { 9 } - [ - 3 ( - \frac { 8 } { 6 } ) + 16 ]$$

Evaluate

$$-\frac{179}{9}\approx -19.888888889$$

Solution Steps

Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.

$$\frac{1}{9}-\left(-3\left(-\frac{4}{3}\right)+16\right)$$

Multiply -3 times -\frac{4}{3}.

$$\frac{1}{9}-\left(4+16\right)$$

Add 4 and 16 to get 20.

$$\frac{1}{9}-20$$

Convert 20 to fraction \frac{180}{9}.

$$\frac{1}{9}-\frac{180}{9}$$

Since \frac{1}{9} and \frac{180}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-180}{9}$$

Subtract 180 from 1 to get -179.

$$-\frac{179}{9}$$

Factor

$$-\frac{179}{9} = -19\frac{8}{9} = -19.88888888888889$$