Solve 1/9*(-2)^2div(-4/3)

$$\frac { 1 } { 9 } \times ( - 2 ) ^ { 2 } \div ( - \frac { 4 } { 3 } )$$

Evaluate

$$-\frac{1}{3}\approx -0.333333333$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$\frac{\frac{1}{9}\times 4}{-\frac{4}{3}}$$

Multiply \frac{1}{9} and 4 to get \frac{4}{9}.

$$\frac{\frac{4}{9}}{-\frac{4}{3}}$$

Divide \frac{4}{9} by -\frac{4}{3} by multiplying \frac{4}{9} by the reciprocal of -\frac{4}{3}.

$$\frac{4}{9}\left(-\frac{3}{4}\right)$$

Multiply \frac{4}{9} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\left(-3\right)}{9\times 4}$$

Cancel out 4 in both numerator and denominator.

$$\frac{-3}{9}$$

Reduce the fraction \frac{-3}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{3}$$

Factor

$$-\frac{1}{3} = -0.3333333333333333$$