Solve 1/9*5/8+(1/2)^3

$$\frac { 1 } { 9 } \times \frac { 5 } { 8 } + ( \frac { 1 } { 2 } ) ^ { 3 }$$

Evaluate

$$\frac{7}{36}\approx 0.194444444$$

Solution Steps

Multiply \frac{1}{9} times \frac{5}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 5}{9\times 8}+\left(\frac{1}{2}\right)^{3}$$

Do the multiplications in the fraction \frac{1\times 5}{9\times 8}.

$$\frac{5}{72}+\left(\frac{1}{2}\right)^{3}$$

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$\frac{5}{72}+\frac{1}{8}$$

Least common multiple of 72 and 8 is 72. Convert \frac{5}{72} and \frac{1}{8} to fractions with denominator 72.

$$\frac{5}{72}+\frac{9}{72}$$

Since \frac{5}{72} and \frac{9}{72} have the same denominator, add them by adding their numerators.

$$\frac{5+9}{72}$$

Add 5 and 9 to get 14.

$$\frac{14}{72}$$

Reduce the fraction \frac{14}{72} to lowest terms by extracting and canceling out 2.

$$\frac{7}{36}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3 ^ {2}} = 0.19444444444444445$$