Solve 1/9div(1-x)+1

$$\frac { 1 } { 9 } \div ( 1 - x ) + 1$$

Evaluate

$$\frac{10-9x}{9\left(1-x\right)}$$

Short Solution Steps

Express \frac{\frac{1}{9}}{1-x} as a single fraction.

$$\frac{1}{9\left(1-x\right)}+1$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{9\left(1-x\right)}{9\left(1-x\right)}.

$$\frac{1}{9\left(1-x\right)}+\frac{9\left(1-x\right)}{9\left(1-x\right)}$$

Since \frac{1}{9\left(1-x\right)} and \frac{9\left(1-x\right)}{9\left(1-x\right)} have the same denominator, add them by adding their numerators.

$$\frac{1+9\left(1-x\right)}{9\left(1-x\right)}$$

Do the multiplications in 1+9\left(1-x\right).

$$\frac{1+9-9x}{9\left(1-x\right)}$$

Combine like terms in 1+9-9x.

$$\frac{10-9x}{9\left(1-x\right)}$$

Expand 9\left(1-x\right).

$$\frac{10-9x}{-9x+9}$$

Factor

$$\frac{10-9x}{9\left(1-x\right)}$$