Solve 1/9*8/4+(2/3)^2

$$\frac { 1 } { 9 } \cdot \frac { 8 } { 4 } + ( \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Divide 8 by 4 to get 2.

$$\frac{1}{9}\times 2+\left(\frac{2}{3}\right)^{2}$$

Multiply \frac{1}{9} and 2 to get \frac{2}{9}.

$$\frac{2}{9}+\left(\frac{2}{3}\right)^{2}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{2}{9}+\frac{4}{9}$$

Since \frac{2}{9} and \frac{4}{9} have the same denominator, add them by adding their numerators.

$$\frac{2+4}{9}$$

Add 2 and 4 to get 6.

$$\frac{6}{9}$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$