Solve 1/80*2x+1/80*8(x+5)=3/4

$$\frac { 1 } { 80 } \times 2 x + \frac { 1 } { 80 } \times 8 ( x + 5 ) = \frac { 3 } { 4 }$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Multiply \frac{1}{80} and 2 to get \frac{2}{80}.

$$\frac{2}{80}x+\frac{1}{80}\times 8\left(x+5\right)=\frac{3}{4}$$

Reduce the fraction \frac{2}{80} to lowest terms by extracting and canceling out 2.

$$\frac{1}{40}x+\frac{1}{80}\times 8\left(x+5\right)=\frac{3}{4}$$

Multiply \frac{1}{80} and 8 to get \frac{8}{80}.

$$\frac{1}{40}x+\frac{8}{80}\left(x+5\right)=\frac{3}{4}$$

Reduce the fraction \frac{8}{80} to lowest terms by extracting and canceling out 8.

$$\frac{1}{40}x+\frac{1}{10}\left(x+5\right)=\frac{3}{4}$$

Use the distributive property to multiply \frac{1}{10} by x+5.

$$\frac{1}{40}x+\frac{1}{10}x+\frac{1}{10}\times 5=\frac{3}{4}$$

Multiply \frac{1}{10} and 5 to get \frac{5}{10}.

$$\frac{1}{40}x+\frac{1}{10}x+\frac{5}{10}=\frac{3}{4}$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$\frac{1}{40}x+\frac{1}{10}x+\frac{1}{2}=\frac{3}{4}$$

Combine \frac{1}{40}x and \frac{1}{10}x to get \frac{1}{8}x.

$$\frac{1}{8}x+\frac{1}{2}=\frac{3}{4}$$

Subtract \frac{1}{2} from both sides.

$$\frac{1}{8}x=\frac{3}{4}-\frac{1}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$\frac{1}{8}x=\frac{3}{4}-\frac{2}{4}$$

Since \frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{8}x=\frac{3-2}{4}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{8}x=\frac{1}{4}$$

Multiply both sides by 8, the reciprocal of \frac{1}{8}.

$$x=\frac{1}{4}\times 8$$

Multiply \frac{1}{4} and 8 to get \frac{8}{4}.

$$x=\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$x=2$$