Solve for h
h=\frac{k}{2\left(2k+1\right)}
k\neq 0\text{ and }k\neq -\frac{1}{2}
Solve for k
k=\frac{2h}{1-4h}
h\neq 0\text{ and }h\neq \frac{1}{4}
Quiz
Linear Equation
5 problems similar to:
\frac { 1 } { 8 h } - \frac { 1 } { 4 k } = \frac { 1 } { 2 }
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k-2h=4hk
Variable h cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8hk, the least common multiple of 8h,4k,2.
k-2h-4hk=0
Subtract 4hk from both sides.
-2h-4hk=-k
Subtract k from both sides. Anything subtracted from zero gives its negation.
\left(-2-4k\right)h=-k
Combine all terms containing h.
\left(-4k-2\right)h=-k
The equation is in standard form.
\frac{\left(-4k-2\right)h}{-4k-2}=-\frac{k}{-4k-2}
Divide both sides by -2-4k.
h=-\frac{k}{-4k-2}
Dividing by -2-4k undoes the multiplication by -2-4k.
h=\frac{k}{2\left(2k+1\right)}
Divide -k by -2-4k.
h=\frac{k}{2\left(2k+1\right)}\text{, }h\neq 0
Variable h cannot be equal to 0.
k-2h=4hk
Variable k cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8hk, the least common multiple of 8h,4k,2.
k-2h-4hk=0
Subtract 4hk from both sides.
k-4hk=2h
Add 2h to both sides. Anything plus zero gives itself.
\left(1-4h\right)k=2h
Combine all terms containing k.
\frac{\left(1-4h\right)k}{1-4h}=\frac{2h}{1-4h}
Divide both sides by 1-4h.
k=\frac{2h}{1-4h}
Dividing by 1-4h undoes the multiplication by 1-4h.
k=\frac{2h}{1-4h}\text{, }k\neq 0
Variable k cannot be equal to 0.
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