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\frac{a^{3}b^{3}+8x^{3}}{8}
Factor out \frac{1}{8}.
\left(2x+ab\right)\left(4x^{2}-2abx+a^{2}b^{2}\right)
Consider a^{3}b^{3}+8x^{3}. Rewrite a^{3}b^{3}+8x^{3} as \left(2x\right)^{3}+\left(ab\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
\frac{\left(2x+ab\right)\left(4x^{2}-2abx+a^{2}b^{2}\right)}{8}
Rewrite the complete factored expression.