Factor
\frac{\left(a-4b\right)\left(a^{2}+4ab+16b^{2}\right)}{8}
Evaluate
\frac{a^{3}}{8}-8b^{3}
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\frac{a^{3}-64b^{3}}{8}
Factor out \frac{1}{8}.
\left(a-4b\right)\left(a^{2}+4ab+16b^{2}\right)
Consider a^{3}-64b^{3}. Rewrite a^{3}-64b^{3} as a^{3}-\left(4b\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
\frac{\left(a-4b\right)\left(a^{2}+4ab+16b^{2}\right)}{8}
Rewrite the complete factored expression.
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