Factor
\frac{\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)}{8}
Evaluate
\frac{a^{3}}{8}+b^{3}
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\frac{a^{3}+8b^{3}}{8}
Factor out \frac{1}{8}.
\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)
Consider a^{3}+8b^{3}. Rewrite a^{3}+8b^{3} as a^{3}+\left(2b\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
\frac{\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)}{8}
Rewrite the complete factored expression.
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