Solve 1/8*58+1/8*41+1/8quad

$$\frac { 1 } { 8 } \times 58 + \frac { 1 } { 8 } \times 41 + \frac { 1 } { 8 } \quad$$

Evaluate

$$\frac{25}{2}=12.5$$

Solution Steps

Multiply \frac{1}{8} and 58 to get \frac{58}{8}.

$$\frac{58}{8}+\frac{1}{8}\times 41+\frac{1}{8}$$

Reduce the fraction \frac{58}{8} to lowest terms by extracting and canceling out 2.

$$\frac{29}{4}+\frac{1}{8}\times 41+\frac{1}{8}$$

Multiply \frac{1}{8} and 41 to get \frac{41}{8}.

$$\frac{29}{4}+\frac{41}{8}+\frac{1}{8}$$

Least common multiple of 4 and 8 is 8. Convert \frac{29}{4} and \frac{41}{8} to fractions with denominator 8.

$$\frac{58}{8}+\frac{41}{8}+\frac{1}{8}$$

Since \frac{58}{8} and \frac{41}{8} have the same denominator, add them by adding their numerators.

$$\frac{58+41}{8}+\frac{1}{8}$$

Add 58 and 41 to get 99.

$$\frac{99}{8}+\frac{1}{8}$$

Since \frac{99}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{99+1}{8}$$

Add 99 and 1 to get 100.

$$\frac{100}{8}$$

Reduce the fraction \frac{100}{8} to lowest terms by extracting and canceling out 4.

$$\frac{25}{2}$$

Factor

$$\frac{5 ^ {2}}{2} = 12\frac{1}{2} = 12.5$$