Solve 1/8+2/3=3/24+16/24=frac{19}{24}

$$\frac { 1 } { 8 } + \frac { 2 } { 3 } = \frac { 3 } { 24 } + \frac { 16 } { 24 } = \frac { 19 } { 24 }$$

Verify

Solution Steps

Least common multiple of 8 and 3 is 24. Convert \frac{1}{8} and \frac{2}{3} to fractions with denominator 24.

$$\frac{3}{24}+\frac{16}{24}=\frac{3}{24}+\frac{16}{24}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Since \frac{3}{24} and \frac{16}{24} have the same denominator, add them by adding their numerators.

$$\frac{3+16}{24}=\frac{3}{24}+\frac{16}{24}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Add 3 and 16 to get 19.

$$\frac{19}{24}=\frac{3}{24}+\frac{16}{24}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Since \frac{3}{24} and \frac{16}{24} have the same denominator, add them by adding their numerators.

$$\frac{19}{24}=\frac{3+16}{24}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Add 3 and 16 to get 19.

$$\frac{19}{24}=\frac{19}{24}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Compare \frac{19}{24} and \frac{19}{24}.

$$\text{true}\text{ and }\frac{3}{24}+\frac{16}{24}=\frac{19}{24}$$

Since \frac{3}{24} and \frac{16}{24} have the same denominator, add them by adding their numerators.

$$\text{true}\text{ and }\frac{3+16}{24}=\frac{19}{24}$$

Add 3 and 16 to get 19.

$$\text{true}\text{ and }\frac{19}{24}=\frac{19}{24}$$

Compare \frac{19}{24} and \frac{19}{24}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$