Solve 1/7^-3*7^-5div(-7)^-2+7^-1=

$$\frac { 1 } { 7 ^ { - 3 } } \times 7 ^ { - 5 } \div ( - 7 ) ^ { - 2 } + 7 ^ { - 1 } =$$

Evaluate

$$\frac{8}{7}\approx 1.142857143$$

Solution Steps

Calculate 7 to the power of -3 and get \frac{1}{343}.

$$\frac{\frac{1}{\frac{1}{343}}\times 7^{-5}}{\left(-7\right)^{-2}}+7^{-1}$$

Divide 1 by \frac{1}{343} by multiplying 1 by the reciprocal of \frac{1}{343}.

$$\frac{1\times 343\times 7^{-5}}{\left(-7\right)^{-2}}+7^{-1}$$

Multiply 1 and 343 to get 343.

$$\frac{343\times 7^{-5}}{\left(-7\right)^{-2}}+7^{-1}$$

Calculate 7 to the power of -5 and get \frac{1}{16807}.

$$\frac{343\times \frac{1}{16807}}{\left(-7\right)^{-2}}+7^{-1}$$

Multiply 343 and \frac{1}{16807} to get \frac{1}{49}.

$$\frac{\frac{1}{49}}{\left(-7\right)^{-2}}+7^{-1}$$

Calculate -7 to the power of -2 and get \frac{1}{49}.

$$\frac{\frac{1}{49}}{\frac{1}{49}}+7^{-1}$$

Divide \frac{1}{49} by \frac{1}{49} to get 1.

$$1+7^{-1}$$

Calculate 7 to the power of -1 and get \frac{1}{7}.

$$1+\frac{1}{7}$$

Add 1 and \frac{1}{7} to get \frac{8}{7}.

$$\frac{8}{7}$$

Factor

$$\frac{2 ^ {3}}{7} = 1\frac{1}{7} = 1.1428571428571428$$