Solve 1/68n^2/3=1/1+0.68*(44.2)^2/3=I

$$\frac { 1 } { 68 n ^ { 2 / 3 } } = \frac { 1 } { 1 + 0.68 \times ( 44.2 ) ^ { 2 / 3 } } = I$$

Evaluate (complex solution)

$$n=\frac{\sqrt{2709375\sqrt[3]{5}\times 221^{\frac{2}{3}}[phone]\sqrt[3]{221}\times 5^{\frac{2}{3}}[phone]}}{1445000}\text{ and }I=\frac{125}{17\sqrt[3]{5}\times 221^{\frac{2}{3}}+125}$$

Solve for n

$$n = -\frac{\sqrt{159375 \sqrt[3]{5} \cdot 221 ^ {\frac{2}{3}} + 4790175 \sqrt[3]{221} \cdot 5 ^ {\frac{2}{3}} + 240346458}}{2} = -9151.381350908958$$

$$n=\frac{\sqrt{159375\sqrt[3]{5}\times 221^{\frac{2}{3}}+4790175\sqrt[3]{221}\times 5^{\frac{2}{3}}[phone]}}{2}\text{, }I=\frac{125}{17\sqrt[3]{5}\times 221^{\frac{2}{3}}+125}$$

Solve for I

$$I = \frac{125}{17 \sqrt[3]{5} \cdot 221 ^ {\frac{2}{3}} + 125} = 0.10525488123057174$$

$$n = \frac{\sqrt{159375 \sqrt[3]{5} \cdot 221 ^ {\frac{2}{3}} + 4790175 \sqrt[3]{221} \cdot 5 ^ {\frac{2}{3}} + 240346458}}{2} = 9151.381350908958$$