Solve 1/64+7/32+1/16-3/64=

$$\frac { 1 } { 64 } + \frac { 7 } { 32 } + \frac { 1 } { 16 } - \frac { 3 } { 64 } =$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Least common multiple of 64 and 32 is 64. Convert \frac{1}{64} and \frac{7}{32} to fractions with denominator 64.

$$\frac{1}{64}+\frac{14}{64}+\frac{1}{16}-\frac{3}{64}$$

Since \frac{1}{64} and \frac{14}{64} have the same denominator, add them by adding their numerators.

$$\frac{1+14}{64}+\frac{1}{16}-\frac{3}{64}$$

Add 1 and 14 to get 15.

$$\frac{15}{64}+\frac{1}{16}-\frac{3}{64}$$

Least common multiple of 64 and 16 is 64. Convert \frac{15}{64} and \frac{1}{16} to fractions with denominator 64.

$$\frac{15}{64}+\frac{4}{64}-\frac{3}{64}$$

Since \frac{15}{64} and \frac{4}{64} have the same denominator, add them by adding their numerators.

$$\frac{15+4}{64}-\frac{3}{64}$$

Add 15 and 4 to get 19.

$$\frac{19}{64}-\frac{3}{64}$$

Since \frac{19}{64} and \frac{3}{64} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-3}{64}$$

Subtract 3 from 19 to get 16.

$$\frac{16}{64}$$

Reduce the fraction \frac{16}{64} to lowest terms by extracting and canceling out 16.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$