Solve 1/6y^2+-3/8y

$$\frac { 1 } { 6 y ^ { 2 } } + \frac { - 3 } { 8 y }$$

Evaluate

$$-\frac{3}{8y}+\frac{1}{6y^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 6y^{2} and 8y is 24y^{2}. Multiply \frac{1}{6y^{2}} times \frac{4}{4}. Multiply \frac{-3}{8y} times \frac{3y}{3y}.

$$\frac{4}{24y^{2}}+\frac{-3\times 3y}{24y^{2}}$$

Since \frac{4}{24y^{2}} and \frac{-3\times 3y}{24y^{2}} have the same denominator, add them by adding their numerators.

$$\frac{4-3\times 3y}{24y^{2}}$$

Do the multiplications in 4-3\times 3y.

$$\frac{4-9y}{24y^{2}}$$

Factor

$$\frac{4-9y}{24y^{2}}$$